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Yes, PDE Toolbox allows the coefficients to be functions of the dependent variables (e.g. temperature). This documentation page ...

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Answered 12 months ago

pdepe uses the variable time step ODE solver, ode15s, internally. http://www.mathworks.com/help/matlab/ref/ode15s.html The...

Answered 1 year ago

There appears to be something wrong with your pdebound function or with how you are passing the handle to it into hyperbolic. D...

6123 views

Responded 1 year ago

Hi, Your geometry is unusual in that none of the rectangles intersect each other. The algorithm in function decsg is designe...

Hi, Solving a 1-D PDE with PDE Toolbox is fairly straightforward. You just define a rectangular region of the appropriate wi...

Answered 2 years ago

Hi, Here is one way to create such a plot. Assume you have the point matrix created by the PDE Toolbox mesher, p, and a solu...

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2 years ago

Hi Chris, Yes, this can be done with PDE Toolbox. The main trick is that you have to replace your 4'th order PDE with two 2'nd...

4583 views

Responded 3 years ago

You didnâ€™t specify but I assume you are interested in solving the time-dependent advection-diffusion equation. Version R2012b o...

4533 views

Responded 2 years ago

Hi, Yes, as others have pointed out, the algorithms in PDE Toolbox are not designed to solve this type of hyperbolic equation i...

3515 views

My understanding of the problem definition is that this user is trying to solve the diffusion equation in a model with two layer...

3146 views

Without seeing your PDE it is impossible to say for certain, but I believe PDE Toolbox could solve your 2-layer diffusion proble...

I suggest taking a look at the adaptmesh function. It does automatic h-refinement of the mesh and often yields more accurate sol...

2722 views

Ah, I see that the documentation page I pointed you to doesn't show you what to do with the pdebound function once you've creat...

Hi, Yes, this is definitely possible. I'll try to point you in the right direction. The function pdegrad can be used to calcu...

This documentation page shows how to specify an f-coefficient on a specific domain: <http://www.mathworks.com/help/pde/ug/sca...

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Answered 11 months ago

I took a look at your attachment and think I understand most, but not all, of the problem you are trying to solve (I don't under...

I ran this example in R2014a of MATLAB and I do get -1 at the lower left corner (and upper right) I created the example in pd...

Yes, pdepe can definitely solve systems of pde. In general, the u argument to the functions you define has as many rows as ther...

There is no support for quadrilateral elements in PDE Toolbox-- either in the meshers or the computational modules. However, if...

From your call to bvpinit where you have this [0.01; 0.9] for the initial guess, it looks like you have 2 differential equation...

There are several ways to define PDE Toolbox coefficients that vary spatially. But, defining the value of the coefficient at eve...

pdenonlin is for solving only PDE that are not a function of time. However, the parabolic function can solve equations that a...

This doesn't exactly answer your question but still may be useful. This example: http://math.mit.edu/cse/codes/mit18086_poiss...

I think that pr = interp1(timedata, tempdata, t) - ur; may be what you need. Assuming the lengths of timedata and temp...

Take a look at this example: <http://www.mathworks.com/help/pde/ug/nonlinear-heat-transfer-in-a-thin-plate.html Nonlinear Hea...

One of the simplest ways to calculate capacitance using PDE Toolbox is from the energy: C = 2*U/V^2 where U is the electrostatic...

I'm afraid I wasn't able to run your example. I believe that your fcoeff function has an error in it. I did take a look at th...

Hi Lena, Yes, you are correct that the Jacobian calculated in parabolic/hyperbolic is only approximate. However, in my experi...

Hi, Unfortunately, I believe you have uncovered a bug in the hyperbolic function that occurs when you have a nonlinear equati...

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