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You can do that by plotting each bar separately. For example, suppose that data is a matrix of 31 x 3 and that the colors for th...

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Answered 9 months ago

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11 months ago

Are you using the function *dot(x,y)* ? If that's so, better use x'*y (assuming that x and y are column vectors) In my...

Answered 1 year ago

Assuming that V =[20 40 10 20 5 10 30 15 25 35]; C ={ {1 2 3}; {5 2 3 1}; {3 4 2 1}; {1 ...

Dear Rhys Taus, I might be wrong, but I think the problem is that you might be rewriting the axes instead of modifying them. ...

Answered 2 years ago

I might not have understood your question, so please let me know if this does not answer it. Suppose that you have a dataset ...

You can do this midpoint=[a,b]; % This defines the midpoint. You should give a and b some value. lineangle=c; % This defines...

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Answered 10 days ago

As far as I can see, there is a problem in the code. Wheneven the condition strcmp(alldata(i,1),alldatafel(j,1)) && strcmp(...

Answered 4 months ago

The problem is in the equation. The constant for the charge of the capacitor is R*C. Therefore, instead of writing Vc = V*(1-...

Answered 5 months ago

The comparison can be done in several different ways. Suppose that X is the original signal and that XR is its reconstruction. Y...

Answered 10 months ago

This solution is based on patch y=-2:.01:2; z=4-y.^2; numy=length(y); % Constructing the vertices V=zeros(numy,3)...

Each section is being played for one second because you are setting that in the line y(1 + timeDomain + (((k+1)/2)-1)*fs) = ...

for a=1000:100:20000 ia=floor(a/100)-9; for b=100:10:200 ib=floor(b/10)-9; for c=.2:.01:.3 ic...

Answered 11 months ago

Maybe you can solve this by setting the axes property 'DataAspectRatio' to a specific value. For example: set(gca,'DataAspe...

How are you creating the patch? Is it only one patch? If you want the patches to be painted, you will need to create two patc...

Dear Noah, Suppose that A is your original matrix and B is the matrix you want to obtain. You could do something like this:...

Try this for j=days_left_in_contract-1:-1:2, counter=days_left_in_contract-j; difference=min(counter,days_left_wi...

scatter draws points without lines connecting them whereas plot may or may not plot the lines, depending on the arguments. sc...

Yes it is! First you need to make a vector b with the labels: b=arrayfun(@(x)num2str(x),a,'UniformOutput',false); Then,...

Suppose that C is your cell array Cnew=C; %Just for not losing original values Cnew(cellfun(@(x)isempty(x),C(:,6)),:)=...

Yes, try this: uicontrol('style','popup','string',{'<HTML><FONT COLOR="red" SIZE="10" FACE="ARIAL"><b><i>Here</i></b></HTML...

How about using find after conversion to numeric value of the answer? ansnum=str2num(answer(1,1)); k=find(dataset==ansnum)...

Hopefully this helps: 1) Save the handles of the ui elements. Suppose that hpopup and hslider are the handles of the pop up m...

You can do that using the following code A=[1 2 3 4 5 6 8 9 10 11 12 13 14]; B=[6 6 6 6 4 4 4 2 2 6 6 4 4]; C=d...

Are the functions polynomials as the example you mentioned? If they are, assume that the order of the polynomial is N (in you...

If I understood correctly, you want the colour to vary according to the value of "z". But the problem is that plot3 takes only o...

You can do the following: nmfinal=mean(cell2mat(squeeze(struct2cell(nm.data))'))'; You might need to take some precautio...

You can just do [any(any(a(:,:,1)>0)),any(any(a(:,:,2)>0))] or just shorter nonzero2D=@(a,k)any(any(a(:,:,k)>0)) ...

Just in case, you could also provide a contextual menu by doing the following hmenu=uicontextmenu; uimenu(hmenu,'Label','M...

Have you tried using the command text()? Suppose that the tip of one of the lines is in (a,b). Then you can just do text(a,b...

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