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Compute log(1+x) accurately for small values of x


y = log1p(x)


y = log1p(x) computes log(1+x), compensating for the roundoff in 1+x. log1p(x) is more accurate than log(1+x) for small values of x. For small x, log1p(x) is approximately x, whereas log(1+x) can be zero.

More About

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Tall Array Support

This function fully supports tall arrays. For more information, see Tall Arrays.

See Also


Introduced before R2006a

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