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This example shows how to analyze a 3-D mechanical part under an applied load using finite element analysis (FEA) and determine the maximal deflection.

The first step in solving a linear elasticity problem is to create a structural analysis model. This is a container that holds the geometry, structural material properties, body and boundary loads, boundary constraints, and mesh.

model = createpde('structural','static-solid');

Import an STL file of a simple bracket model using the `importGeometry`

function. This function reconstructs the faces, edges and vertices of the model. It can merge some faces and edges, so the numbers can differ from those of the parent CAD model.

`importGeometry(model,'BracketWithHole.stl');`

Plot the geometry and turn on face labels. You will need the face labels to define the boundary conditions.

figure pdegplot(model,'FaceLabels','on') view(30,30); title('Bracket with Face Labels')

figure pdegplot(model,'FaceLabels','on') view(-134,-32) title('Bracket with Face Labels, Rear View')

Specify Young's modulus and Poisson's ratio for this material.

structuralProperties(model,'Cell',1,'YoungsModulus',200e9, ... 'PoissonsRatio',0.3);

The problem has two boundary conditions: the back face (face 4) is immobile and the front face has an applied load. All other boundary conditions, by default, are free boundaries.

structuralBC(model,'Face',4,'Constraint','fixed');

Apply a distributed load in the negative $$z$$-direction to the front face (face 8).

distributedLoad = 1e4; % Applied load in Pascals structuralBoundaryLoad (model,'Face',8,'SurfaceTraction',[0;0;-distributedLoad]);

Create a mesh that uses 10-node tetrahedral elements with quadratic interpolation functions. This element type is significantly more accurate than the linear interpolation (four-node) elements, particularly in elasticity analyses that involve bending.

bracketThickness = 1e-2; % Thickness of horizontal plate with hole, meters generateMesh(model,'Hmax',bracketThickness); figure pdeplot3D(model) title('Mesh with Quadratic Tetrahedral Elements');

Use `solve`

to calculate the solution.

result = solve(model);

Find the maximal deflection of the bracket in the $$z$$ direction.

```
minUz = min(result.Displacement.uz);
fprintf('Maximal deflection in the z-direction is %g meters.', minUz)
```

Maximal deflection in the z-direction is -4.48952e-05 meters.

To see the solution, plot the components of the solution vector. The maximal deflections are in the $$z$$-direction. Because the part and the loading are symmetric, the $$x$$-displacement and $$z$$-displacement are symmetric, and the $$y$$-displacement is antisymmetric with respect to the center line.

Here, the plotting routine uses the `'jet'`

colormap, which has blue as the color representing the lowest value and red representing the highest value. The bracket loading causes face 8 to dip down, so the maximum $$z$$-displacement appears blue.

figure pdeplot3D(model,'ColorMapData',result.Displacement.ux) title('x-displacement') colormap('jet')

figure pdeplot3D(model,'ColorMapData',result.Displacement.uy) title('y-displacement') colormap('jet')

figure pdeplot3D(model,'ColorMapData',result.Displacement.uz) title('z-displacement') colormap('jet')

Plot values of the von Mises Stress at nodal locations. Use the same `jet`

colormap.

figure pdeplot3D(model,'ColorMapData',result.VonMisesStress) title('von Mises stress') colormap('jet')