A = convmtx(h,n)
A = convmtx(h,n) returns the
A, such that the product of
x, is the convolution of
h is a column vector of length
the product of
A and a column vector,
n is the convolution of
h is a row vector of length
the product of a row vector,
x, of length
the convolution of
convmtx handles edge conditions
by zero padding.
It is generally more efficient to compute a convolution using
conv when the signals are vectors. For multichannel signals,
convmtx might be more efficient.
Compute the convolution of two random vectors,
b, using both
convmtx. The signals have 1000 samples each. Compare the time spent by the two functions. Eliminate random fluctuations by repeating the calculation 30 times and averaging.
Nt = 30; Na = 1000; Nb = 1000; tcnv = 0; tmtx = 0; for kj = 1:Nt a = randn(Na,1); b = randn(Nb,1); tic n = conv(a,b); tcnv = tcnv+toc; tic c = convmtx(b,Na); d = c*a; tmtx = tmtx+toc; end t1col = [tcnv tmtx]/Nt t1rat = tcnv\tmtx
t1col = 0.0026 0.2002 t1rat = 78.3110
conv is about two orders of magnitude more efficient.
Repeat the exercise for the case where
a is a mutichannel signal with 1000 channels. Optimize
conv's performance by preallocating.
Nchan = 1000; tcnv = 0; tmtx = 0; n = zeros(Na+Nb-1,Nchan); for kj = 1:Nt a = randn(Na,Nchan); b = randn(Nb,1); tic for k = 1:Nchan n(:,k) = conv(a(:,k),b); end tcnv = tcnv+toc; tic c = convmtx(b,Na); d = c*a; tmtx = tmtx+toc; end tmcol = [tcnv tmtx]/Nt tmrat = tcnv/tmtx
tmcol = 1.1815 0.7431 tmrat = 1.5900
convmtx is about 3 times as efficient as