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how to get updated value of function everytime in the loop

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Hello. I am using the below code in the loop and here is the problem area. When I use the code(following)
for i=1:100,
G=i;
A=[-1/10 0;G -(1+10*G)/10];
B=[2 2 0;2 G G];
C=[1 -1];
I=[1 0;0 1];
syms s
Q=C*((s*I-A)^(-1))*B;
Q(2);
Q(3);
syms t
M=(ilaplace(Q(2),s,t))^2;
N=(ilaplace(Q(3),s,t))^2;
m=integral(M,0,Inf);
n=integral(N,0,Inf);
Sw=1;Sv=100;
Ess(i,:)=Sw*m+Sv*n;
We(i,:)=Sw*m;Ve(i,:)=Sv*n;
end
Error using integral (line 83) First input argument must be a function handle.
*now i think the error is in the line where I use M=(ilaplace(Q(2),s,t))^2; and N=(ilaplace(Q(3),s,t))^2;, but how else I can achieve to calculate the integral as each time the value of G is different in each loop and hence I cannot write M and N as function of t because it changes every time the loop is executed depending on the value of G. *

Accepted Answer

Walter Roberson
Walter Roberson on 28 Feb 2014
Edited: Walter Roberson on 28 Feb 2014
ilaplace is a symbolic transform, giving you a symbolic result. You need to convert the symbolic result to a function handle. See matlabFunction() for that.
Or you could consider using symbolic integration, int() instead of integral()
  2 Comments
upinderjeet
upinderjeet on 28 Feb 2014
Dont you think that in both the cases you recommend, I still have to write the expression for that symbolic function before I cud use a function handle or int. If I am right then how can I cater to the changing value of that expression every time the new loop is being executed.

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