Asked by Venkatesh Deshpande
on 20 Mar 2014

Hello, Can anybody help me? I want to figure out where I am doing a mistake in program. The only variable is X and Cp is an input.

Cp = double(zeros(49792,1)); P = size(x.Time_Series); Q = P(1,1);

Cp(1,1)= 0.126826003999670; Cp(2,1)= 0.325943036562508;

for k=3:Q; k hx = inline( '12.175*(X - 2*Cp(k-1,1) + Cp(k-2,1)) + 13.525*((X - Cp(k-1,1))* abs(X - Cp(k-1,1))) + X - SINGLE_FINAL_TIME_SERIES_OF_TAPS_NEAR_DOMINANT_OPENING(k,1)','X',Cp); hp = fzero (hx,0,Cp,SINGLE_FINAL_TIME_SERIES_OF_TAPS_NEAR_DOMINANT_OPENING(k,1)); Cp(k) = hp(1); end I am getting this error Error: The expression to the left of the equals sign is not a valid target for an assignment.

If in inline function, I remove Cp which is given after X (at the very last near the bracket), then it shows error: too many inputs to inline function. Pls help. thanks.

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Answer by Star Strider
on 20 Mar 2014

Accepted Answer

It doesn’t like the `‘==’` in `SINGLE_FINAL_TIME_SERIES_OF_TAPS_NEAR_DOMINANT_OPENING(k,1)==0`.

Unlike anonymous functions that use workspace variables, `inline` functions ignore anything that isn’t in their argument list. It has no idea what `SINGLE_FINAL_TIME_SERIES_OF_TAPS_NEAR_DOMINANT_OPENING(k,1)` or `k` are.

Also, `fzero` only accepts single-variable functions.

Venkatesh Deshpande
on 23 Mar 2014

Star Strider
on 23 Mar 2014

My pleasure!

Wow! And a tribute, too! Thank you!

I have a background in physical chemistry and am an instrument-rated private pilot, so I'm slightly familiar with what you are doing. I do not have sufficient background in fluid dynamics to understand it in any detail, though.

Venkatesh Deshpande
on 23 Mar 2014

Thanks for helping and telling about your background. Take care.

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Answer by Sean de Wolski
on 20 Mar 2014

Avoid using `inline`, instead use an anonymous function

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