Interpolating new datetime format

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Tom
Tom on 8 Oct 2014
Commented: Tom on 8 Oct 2014
Hi, I'm updating some code to use the new datetime format in 2014b for plotting and display purposes, but I'm struggling to interpolate my data. Previously I was using the line below where Data.Time and NewData.Time were datenum, but now I've converted them to the datetime format, I can no longer interpolate it. Is there an easy way around this?
NewData.Latitude = interp1(Data.Time,Data.Latitude,NewData.Time);
Thanks, Tom

Accepted Answer

the cyclist
the cyclist on 8 Oct 2014
I could not figure out a way to do this without (ironically) needing to convert the datetime object back to a datenum [in order to have a numeric value for interp1() to operate on].
I thought that maybe defining the time and data as a timeseries object and then using the resample command would work, but it seems that that method also requires something more datenum-y.
  1 Comment
Tom
Tom on 8 Oct 2014
Same, for anyone else, I got it working with the following code;
NewData.Latitude = interp1(datenum(Data.Time),Data.Latitude,datenum(NewData.Time));

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