Bringing arrays to the same length

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Lev Mihailov
Lev Mihailov on 2 Mar 2022
Edited: Rik on 2 Mar 2022
There are three arrays (two vectors and a matrix), I need to bring them to the same length
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values ​​in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
% what do i need to get
ba=[ 1.2,1.3,1.4];
ma=[1,2;1,2;1,0];
I will be glad to any advice
  2 Comments
Benjamin Kraus
Benjamin Kraus on 2 Mar 2022
I'm having some trouble understanding your question.
If I understand correctly, you are trying to calculate the values in ba and ma based somehow on the values of a, b, and m, but I don't see how you calculate the values in ma from any of the vectors, and ba appears to be equal to a. Can you give more description (in words) of the algorithm you are hoping to use to derive ba and ma based on a, b, and m?

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Answers (2)

Rik
Rik on 2 Mar 2022
Edited: Rik on 2 Mar 2022
There are two issues with the solution by Arif:
  • It uses find on a logical array, but that is only used to index an array
  • It assume the the first column in m will be 1 for all the rows we're looking for
The edits below solve both.
a=[ 1.2,1.3,1.4];
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[L,idx]=ismember(a,b); % find the element of a in b
ba=a(L)
ba = 1×3
1.2000 1.3000 1.4000
ma=m(idx(L),:)
ma = 3×2
1 2 1 2 1 0

Arif Hoq
Arif Hoq on 2 Mar 2022
Edited: Arif Hoq on 2 Mar 2022
try this:
a=[ 1.2,1.3,1.4]; % by array "a" i need to sort the values in array "b" and "m"
b=[ 1.2,0.9,1.3,2.6,1.4];
m=[1,2;26,90;1,2;120,0;1,0];
[idx]=find(ismember(b,a)); % find the element of a in b
ba=b(idx)
ba = 1×3
1.2000 1.3000 1.4000
ma=m((m==1),:) % find the first element=1
ma = 3×2
1 2 1 2 1 0

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