How to apply dec2bin to char array?

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Ammy
Ammy on 11 Mar 2022
Edited: Stephen23 on 12 Mar 2022
I have a data as char
a ='1234567';
dec2bin(a) gives
6×6 char array
'110001'
'110010'
'110011'
'110100'
'110101'
'110110'
but I want the result like dec2bin(123456)= '11110001001000000'
How to apply dec2bin to a char value to get a sinle out put ?
  1 Comment
Stephen23
Stephen23 on 11 Mar 2022
a ='1234567';
b = dec2bin(str2double(a))
b = '100101101011010000111'

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Accepted Answer

Stephen23
Stephen23 on 12 Mar 2022
Edited: Stephen23 on 12 Mar 2022
"there is a problem with more digits in a like a='12362534624362643243256346523462'..."
The DOUBLE numeric class can only store 15 or so decimal digits or precision, it cannot store that entire number that you have shown without some loss of information. So converting to a scalar numeric using STR2NUM, STR2DOUBLE, SSCANF, or something similar simply will not work if you want all of the information. You will have to find an alternative approach, for example download BASE2BASE:
and use it like this:
a = '12362534624362643243256346523462';
b = base2base(a,10,2)
b = '10011100000010011000000011110110100110100000111111110111001000110111011110100110000110110011011101000110'

More Answers (1)

KSSV
KSSV on 11 Mar 2022
a ='1234567';
dec2bin(str2num(a))
ans = '100101101011010000111'
  1 Comment
Ammy
Ammy on 12 Mar 2022
@KSSV Thank you, but there is a problem with more digits in a
like
a='12362534624362643243256346523462'
str2num(a)= 1.2363e+31
and then not giving the right output in binary form

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