understanding the reshape function

1 view (last 30 days)
Miguel Albuquerque
Miguel Albuquerque on 12 Jul 2022
Edited: Jan on 12 Jul 2022
Hey guys, I dont seem to undertsand what does this mean, I vre read a lot of thing, but this code is not explicit what it does, thank you.
surveillance_reshaped = reshape(Surveillance_signal, 100000, 1, []);
reference_reshaped = reshape(Reference_signal, 1000, 1, []);

Accepted Answer

Jan
Jan on 12 Jul 2022
Edited: Jan on 12 Jul 2022
reshape changes the dimensions of an array without changing the number of elements or their order. If you provide an empty matrix as dimension, the other given dimensions are used and the missing one is replaced such, that the total number of elements is not modified. So reshape(X, 1, []) creates a row vector.
It matters, that Matlab stores the element of arrays in columnwise order:
X = [1, 2; ...
3, 4; ...
5, 6];
reshape(X, 1, []) % or explicitly: reshape(X, 1, 6)
ans = 1×6
1 3 5 2 4 6
With providing more dimensions, a multi-dimonsional array is created:
reshape(X, 2, 1, [])
ans =
ans(:,:,1) = 1 3 ans(:,:,2) = 5 2 ans(:,:,3) = 4 6

More Answers (0)

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Tags

Products


Release

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!