Is there a more efficient way to format my vector rather than manually change the code
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T = 5400;
INT = 900;
tme = 0:INT:T;
TV = [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12, tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
I have this code, however is there an easier way to code this if i want to change the values for 'T' and 'INT' to any random value, for the' TV' vector to automatically update rather than me manually put tme(1), tme(2) etc for those respective values in the 'tme' vector
2 Comments
Bruno Luong
on 16 Aug 2022
Edited: Bruno Luong
on 16 Aug 2022
Until you explain the law to obtain steps 30, 15, 12, 2.4, 2.1428, 2.5, then no you have to enter it by hand.
Accepted Answer
David Hill
on 16 Aug 2022
TV =@(tme) [tme(1):30:tme(2)-30, tme(2):15:tme(3)-15, tme(3):12:tme(4)-12,...
tme(4):2.4:tme(5)-2.4, tme(5):2.1428:tme(6)-2.1428, tme(6):2.5:tme(7)-2.5];
tv1=TV(0:900:5400);
tv2=TV(0:500:5000);
5 Comments
John D'Errico
on 16 Aug 2022
It IS (sort of) an answer to your question as posed. I (or anyone) might have been moved to answer a separate question, that was posed more accurately, OR an unaccepted and clarified question. You might even find that David then makes his answer a general solution then.
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