How to find intersection points between plot and straight line

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I tried to find the intersection points of the attached figure using the following code provided to me which worked for a different figure.
h1c = get(gca, 'Children');
Xdc = get(h1c, 'XData');
Ydc = get(h1c, 'YData');
maxlen = max(cell2mat(cellfun(@max, cellfun(@size, Xdc, 'Uni',0),'Uni',0)))
Xd2 = cell2mat(Xdc(2));
Yd2 = cell2mat(Ydc(2));
Xd = Xd2;
Yd1 = cell2mat(Ydc(1));
Yd = [Yd1(1)*ones(size(Xd2)); Yd2];
% CALCULATIONS:
Ydn = diff(Yd, [], 1); % Subtract line from curve to create zero-crossings
Zx = circshift(Ydn, [0 1]) .* Ydn; % Use circshift to detect them
Zxi = find(Zx < 0); % Their indices
for k1 = 1:length(Zxi) % Use interp1(Y,X,0) to get line intercepts as Xzx
Xzx(k1) = interp1([Ydn(Zxi(k1)-1) Ydn(Zxi(k1))], [Xd(1,Zxi(k1)-1) Xd(1,Zxi(k1))], 0);
end
% PLOT ZERO-CROSSINGS ON FIGURE TO CHECK:
hold on
plot(Xzx, repmat(Yd(1,1),1,length(Xzx)), '*r')
hold off
It returns with the error
Error using cellfun
Input #2 expected to be a cell array, was double instead.
And Im not quite sure how to fix it

Accepted Answer

Star Strider
Star Strider on 22 Mar 2015
That is my code, so I sort of remember what I was doing when I wrote it here nine months ago (in R2014a). What version of MATLAB are you using?
I’ll do my best to help, but I can’t figure out what you want to do. I don’t see a reference line in ‘Curve figure.fig’.
  6 Comments
Vaultec
Vaultec on 23 Mar 2015
Thank you very much,
So the reason your previous code didnt work was it because of a version issue?
Star Strider
Star Strider on 23 Mar 2015
My pleasure.
I don’t believe it was a version issue, but that for some reason the blue curve didn’t appear as 'XData' or 'YData' when I tried to get them from the figure. (The half-power line may have overwritten them somehow, without erasing the blue curve.) I didn’t explore that in my latest code, since I had all the data in the spreadsheet file. You may want to, because a .fig file is actually a very good way to transport both the data and the concept you want to (literally) illustrate.

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