# Create a random Matrix

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I have a 8 column vector n*1. Can I create a Random matrix of n*8?

The function must take one value from each vector and create a matrix with 8 columns and n rows.

Please help me :-)

##### 2 Comments

Jan
on 24 Oct 2011

### Accepted Answer

Andrei Bobrov
on 24 Oct 2011

A1,A2,..,A8 - your vectors (nx1), let n = 5;

for j1 = 1:8, eval([sprintf('A%d',j1),'=randi(20,5,1)']); end

A = eval(['[',sprintf('A%d,',1:8),']'])

out=A(bsxfun(@plus,cell2mat(arrayfun(@(x)randperm(n)',(1:8),'un',0)),(0:7)*n))

##### 3 Comments

### More Answers (1)

Walter Roberson
on 24 Oct 2011

rv(:,1) = randomvector1;

rv(:,2) = randomvector2;

rv(:,3) = randomvector3;

....

rv(:,4) = randomvector4;

rants = zeros(8, n);

for K = 1:n

rants(:,K) = A Random Selection of One Entry Per Column from rv

end

How to do "A Random Selection of One Entry Per Column from rv" is left to you to work on in more detail. I will hint that it involves using rand().

##### 3 Comments

Walter Roberson
on 30 Oct 2011

floor(1 + n * rand())

will give you a random row number.

If I say much more than I will be completing your assignment for you.

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