Create vector only containing consecutive numbers of other vector

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Hi, I'm searching for a possibility to build a vector B which only contains the consecutive numbers of vector A. I tried it like this but it is not working. Can someone help me?
A=[2 5 6 7]; B=0; for m=1:length(A)-1 if diff(A)==1 B=A(m); m=m+1; end end
The anwser should look like this: B=[5 6 7]

Accepted Answer

Guillaume
Guillaume on 30 Mar 2015
Edited: Guillaume on 30 Mar 2015
Using just diff and logical operations (no find):
A = [2 5 6 7 10 12 13 20];
dA = diff(A) == 1;
B = A([0 dA] | [dA 0])
This assumes that A is a row vector.

More Answers (1)

Stephen23
Stephen23 on 30 Mar 2015
For large vectors using logical indexing will probably be faster than using find:
>> A = [2,5,6,7];
>> X = diff(A)==1;
>> Y = [false,X] | [X,false];
>> A(Y)
ans =
5 6 7
  6 Comments
Star Strider
Star Strider on 31 Mar 2015
I delete my Answers if they are neither Accepted nor Voted. Many others do as well.

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