I'm getting a matrix error of inconsistently on line 45, any tips how I can fix it.
1 view (last 30 days)
Show older comments
N=10;
L=10;
D=.01;
dt=.01;
k_on=1;
k_off=.1;
F=1;
tmax=100;
x=L*rand(N,1);
y=L*rand(N,1);
state=zeros(N,1);
figure;
axis([0 L 0 L]);
set(gca,'nextplot','replacechildren');
for t = 0:dt:tmax
dx=sqrt(2*D*dt)*randn(N,1);
dy=sqrt(2*D*dt)*randn(N,1);
x=x+dx;
y=y+dy;
x(x<0)=0;
x(x>L)=L;
y(y<0)=0;
y(y>L)=L;
p_on=k_on*dt*F;
p_off=k_off*dt;
for i = 1:N
if state(i)==0
if rand < p_on
state(i)=1;
end
else
if rand<p_off
state(i)=0
end
end
end
colors= repmat([1 0 0], N,1);
colors(state == 1,:,:) = repmat([0 1 0],sum(state),1);
scatter(x,y,50,colors,'filled');
title(sprintf('Time=%.2f',t));
drawnow;
if any(state == 1)
p_bind=1-exp(-k_on*dt*F);
if rand<p_bind
[~,i]=max(state);
state(i)=2;
colors(i,:)=[0]
end
end
end
1 Comment
Walter Roberson
on 1 May 2023
What is the difference between this and https://www.mathworks.com/matlabcentral/answers/1955619-i-keep-getting-this-matrix-error-when-i-run-my-code-any-tips-how-i-can-fix-it-its-line-45?s_tid=srchtitle ?
Answers (1)
LeoAiE
on 1 May 2023
It seems there is an issue with the assignment of the colors variable in the last part of your code.
N=10;
L=10;
D=.01;
dt=.01;
k_on=1;
k_off=.1;
F=1;
tmax=100;
x=L*rand(N,1);
y=L*rand(N,1);
state=zeros(N,1);
figure;
axis([0 L 0 L]);
set(gca,'nextplot','replacechildren');
for t = 0:dt:tmax
dx=sqrt(2*D*dt)*randn(N,1);
dy=sqrt(2*D*dt)*randn(N,1);
x=x+dx;
y=y+dy;
x(x<0)=0;
x(x>L)=L;
y(y<0)=0;
y(y>L)=L;
p_on=k_on*dt*F;
p_off=k_off*dt;
for i = 1:N
if state(i)==0
if rand < p_on
state(i)=1;
end
else
if rand<p_off
state(i)=0
end
end
end
colors = repmat([1 0 0], N,1);
colors(state == 1,:,:) = repmat([0 1 0],sum(state == 1),1);
scatter(x,y,50,colors,'filled');
title(sprintf('Time=%.2f',t));
drawnow;
if any(state == 1)
p_bind=1-exp(-k_on*dt*F);
if rand<p_bind
[~,i]=max(state);
state(i)=2;
colors(i,:)=[0 0 1]; % Corrected color assignment
end
end
end
See Also
Categories
Find more on Annotations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!