Why did the loop terminate so early?

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When I ran the following loop:
for i = 1 : 5^15
%
end
i
Matlab(R2007b) terminated when i equals 2^31-1 (2147483647). That's way too early. Do anyone have an explanation?

Accepted Answer

the cyclist
the cyclist on 2 Apr 2015
Edited: the cyclist on 2 Apr 2015
That is of course a quite ancient version. In MATLAB 2015a, the loop continues all the way to 5^15.
2^31-1 is the maximum representable integer in a 32-bit version of MATLAB, which yours is. I don't know the specifics, but it is presumably related to that.
What class of variable is i? I actually would have expected it to be a double, and therefore you would not have this problem.
  1 Comment
YEN
YEN on 2 Apr 2015
The variable i is actually a "double" so it should not be limited to 2^31-1. So strange. Thanks anyway.

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