Linear Regression Matlab code

6 views (last 30 days)
Hello, this is my matlab script that is supposed to take data from an excel spread sheet and use it to create a y = mx+b function by linear regression. Here is my code and attached is the excel spread sheet. The first row is the amount in gallons and the next two rows are the amount of time it took to move the gallons in seconds.
points = xlsread('data.xlsx');
n = size(points,1);
sum_x = 0;
sum_y = 0;
sum_xy = 0;
sum_x2 = 0;
for i = i:n
sum_x = sum_x + points(i,2);
sum_y = sum_y + points(i,3);
sum_xy = sum_xy + points(i,2)*(points(i,3));
sum_x2 = sum_x2 + (points(i,2)^2);
end
a1 = (n*sum_xy - sum_x*sum_y)/(n*sum_x2 - sum_x2);
a0 = (sum_y/n)-a_1*(sum_x/n);
y_new = a1*x + a_0;
THank you for your help.
  5 Comments
Image Analyst
Image Analyst on 27 Apr 2015
You haven't defined your x variable yet, like Mohammad did where he called x "gModel" - a more descriptive name than the generic "x". It looks like his code should work. If it does, Vote for it and then click "Accept this answer" .
Or Hirshfeld
Or Hirshfeld on 27 Apr 2015
I would use curve fitting function in matlab instead of summing in iterations and calculated formulas.

Sign in to comment.

Accepted Answer

Mohammad Abouali
Mohammad Abouali on 27 Apr 2015
% First COLUMN is galon, the next two columns are amount of time required
% to remove that amount of gallons. I assumed you have two sets of
% measurements that's why there are two columns.
data=[ 0.50 66 70; ...
0.75 100 95; ...
1.00 129 135; ...
1.25 161 159; ...
1.50 198 190; ...
1.75 230 232; ...
2.00 265 250];
% Fitting a a polynomial t=a1*g+a0; g: Gallon, t: time
g=[data(:,1);data(:,1)];
tMeasured=[data(:,2);data(:,3)];
a=polyfit(g, tMeasured,1);
% Plot1
gModel=min(g):0.01:max(g);
tModelled=polyval(a,gModel);
figure
plot(gModel,tModelled,'r-','LineWidth',2);
hold on
plot(g,tMeasured,'kx','MarkerSize',10)
legend('Fitted Line','Measured','Location','NorthWest');

More Answers (0)

Categories

Find more on Descriptive Statistics in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!