How to extract only part of a file name

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I am trying to extract a file but i don´t want to extract it´s entire name. For example:
In
inv_1000061014358_20150424_115235
I only want to extract inv_1000061014358.
Can anyone help?
Thanks!!!!

Accepted Answer

dpb
dpb on 19 May 2015
Edited: dpb on 19 May 2015
Presuming the numeric substring isn't the same length always,
ix=strfind(s,'_'); % get the underscore locations
t=s(1:ix(2)-1); % return the substring up to 2nd underscore
One can also use find to only get the first two locations; would be handy if it also had the ability to return an N th argument instead of just first or last N; then wouldn't have to use the intermediate index vector.
Or, one can use regexp

More Answers (1)

Guillaume
Guillaume on 19 May 2015
Edited: Guillaume on 19 May 2015
In this sort of cases, I would use a regular expression just because it expresses better that you want to extract a portion of the string that conform to a particular pattern.
It's not obvious from the question what that pattern is. Assuming it is: 1 or more alphabetic characters, an underscode, one or more numbers, before another underscore, then:
s = 'inv_1000061014358_20150424_115235';
ss = regexp(s, '^[a-z]+_\d+(?=_)', 'match', 'once')
If regular expressions look too daunting then dpb's answer is the way to go.

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