d(phi)/dt=​laplaciano​(-phi+phi^​3-laplacia​no(phi)) given boundary conditions and a initial state (strange result)

1 view (last 30 days)
DDD
DDD on 2 Jun 2015
Commented: DDD on 2 Jun 2015
It is given d(phi)/dt=laplaciano(-phi+phi^3-laplaciano(phi)) to solve in a square 30*30 (L=30).
It is also mentioned that phi(1, y) = 1 and phi(L, y) =

Sign in to answer this question.

Answers (0)

Categories

Find more on Ordinary Differential Equations in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!