Index exceeds matrix dimensions, error problem

When I run this code, where no. of rows in l is 1 less than that of p. Can someone find the problem as i am not able to! Thanks in advance

% code
[n,~]=size(p);
area=zeros(n,1);
if n>2
  for z=2:n-1
      ls=l(z-1:z,:);
      ps=p(z-1:z+1,:);
      rms=[p(z,6):-5:minr,minr];
      i=size(rms);
      aream=1e+137;
      for ii=1:i
          rm=[0;rms(ii);0];
          disp(num2str(rms(ii)))
          fitting_curve(ls,ps,rm,w)
          obstacle=splitPolygons(obs);
          for o=1:1:N
              obst = transpose(cell2mat(obstacle(o)));
              area(ii) = area(ii)+area_intersection(curve,road,obst);
          end
          if area(ii)<aream
          aream=area(ii);
          p(z,9)=rms(ii);
          end
      end
  end
end

It shows following error

% code
Index exceeds matrix dimensions.
Error in minrad (line 8) ls=l(z-1:z,:);

Answer 1

[Walter Roberson]

You are failing while indexing ls, an array whose size we have no information about. We do not know that it has at least as many rows as p has (or perhaps one fewer)

[aaditya taparia]

What is the solution? Thanks.

[Torsten]

The solution is to check whether the matrix l has at least (n-1) rows.

If not, you will receive the above error message.

Best wishes

Torsten.