if loop not executing
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i have dataset of 80 numbers=[1:1:80]
now i want to take first 8 values ,multiply each value by 2 and divide each by 2,so i will have 8 values each for multiplication and division,and then want to find average for that multilaction values and division values,same way i want to perform for those 80 values from 1st 8,2nd 8,3rd 8........10th8 please help..
i tried the folowing but it is not executing
z=0
if index<=8 +z
Sum=index+2
mul=index.*2
end
avg=mean(Sum)
avg=mean(mul)
z=z+1
i get answer as z=0
z=1
please help
4 Comments
Walter Roberson
on 28 Dec 2011
There is no such thing as an "if loop". There is "for loop" and "while loop" and "if statement", but not "if loop".
Accepted Answer
bym
on 28 Dec 2011
use reshape to organize your values into 8 rows and 10 columns. You can then use mean() after your multiplications & divisions.
x = 1:80;
x = reshape(x,8,[]);
...
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More Answers (2)
Image Analyst
on 28 Dec 2011
I answered this where you first asked it http://www.mathworks.com/matlabcentral/answers/24562-selecting-an-image-from-folder My answer of using conv was also suggested by someone else in your third thread for this http://www.mathworks.com/matlabcentral/answers/24848-performing-certain-operation-from-a-set-a-certain-set-of-values
Can you explain in words what you actually want to do? Is it a running average? Or something else?
2 Comments
Image Analyst
on 29 Dec 2011
For example, output(1) = mean(input(1):input(8)), output(2) = mean(input(2):input(9)) and so on, moving over one element at a time.
Fangjun Jiang
on 28 Dec 2011
if-else statement won't do any loop.
I assume this is an exercise. You almost need to re-work on the code completely.
"multiply each value by 2 and divide each by 2", but you are adding it by 2.
It's meaningless to do mean() on a scalar.
I suggest you go to the MATLAB document, MATLAB->Getting Started.
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