if loop not executing

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kash
kash on 28 Dec 2011
i have dataset of 80 numbers=[1:1:80]
now i want to take first 8 values ,multiply each value by 2 and divide each by 2,so i will have 8 values each for multiplication and division,and then want to find average for that multilaction values and division values,same way i want to perform for those 80 values from 1st 8,2nd 8,3rd 8........10th8 please help..
i tried the folowing but it is not executing
z=0
if index<=8 +z
Sum=index+2
mul=index.*2
end
avg=mean(Sum)
avg=mean(mul)
z=z+1
i get answer as z=0
z=1
please help
  4 Comments
Walter Roberson
Walter Roberson on 28 Dec 2011
There is no such thing as an "if loop". There is "for loop" and "while loop" and "if statement", but not "if loop".
kash
kash on 29 Dec 2011
ok walter it is "if statement"

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Accepted Answer

bym
bym on 28 Dec 2011
use reshape to organize your values into 8 rows and 10 columns. You can then use mean() after your multiplications & divisions.
x = 1:80;
x = reshape(x,8,[]);
...

More Answers (2)

Image Analyst
Image Analyst on 28 Dec 2011
Can you explain in words what you actually want to do? Is it a running average? Or something else?
  2 Comments
kash
kash on 28 Dec 2011
Actually i need in final of 10 average values in sum and multiplication,and i need each
foe example
the sum of first 8 values must be stored in an variable and so on till end(last 8 values)and same for multiplication,and average also
i dont know what u mean by running average
Image Analyst
Image Analyst on 29 Dec 2011
For example, output(1) = mean(input(1):input(8)), output(2) = mean(input(2):input(9)) and so on, moving over one element at a time.

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Fangjun Jiang
Fangjun Jiang on 28 Dec 2011
if-else statement won't do any loop.
I assume this is an exercise. You almost need to re-work on the code completely.
"multiply each value by 2 and divide each by 2", but you are adding it by 2.
It's meaningless to do mean() on a scalar.
I suggest you go to the MATLAB document, MATLAB->Getting Started.

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