Filling Cell Array with Empty value

Hi Everyone

I have cell arracy call Reults look like given below 4x1 cell

3x1 cell

4x1 cell

3x1 cell

4x1 cell

4x1 cell

4x1 cell

4x1 cell

4x1 cell

4x1 cell

5x1 cell

4x1 cell

4x1 cell

5x1 cell

I want to do the dimension equal of each cell by filling with empty value so that it becomes like 5x1 cell

5x1 cell

5x1 cell

5x1 cell ... and so on.

Can any one help ? It would be great to check if dimension of any cell in a cell called 'Result' is less than 5 say 4x1 make it 5x1 by inseting the empty value at last.

If the check is not possible it is fine to make every cell with in cell call 'Result' 5x1

Thanks in advance.

Answer 1

[Thorsten]

for i = 1:numel(Result)
  [r, c]= size(Result{i});
  assert(c == 1, 'Number of columns must be 1.') 
  if r < 5, Result{i}{5,1} = []; end
end

[Abi Waqas]

Dear

thanks for response, i found another solution. The solution you gave is right but was not suiting my problem.

Thanks alot :)

[Avinash Dass]

Dear Abi,

Can you provide me your solution ?

Thanks in advance.

Answer 2

[Stephen Cobeldick]

As an alternative you can easily remove one level of the cell nesting:

V = {{0;1;2};{3;4;5;6};{7;8;9}};
for k = numel(V):-1:1
    Z(1:numel(V{k}),k) = V{k};
end

This produces a cell array without other cells nested inside it, each column is one of the cells of the original array (swap the Z-indices to make this the rows):

>> Z
Z = 
    [0]    [3]    [7]
    [1]    [4]    [8]
    [2]    [5]    [9]
     []    [6]     []

It may be easier to access the contents:

>> Z(:,2)
ans = 
    [3]
    [4]
    [5]
    [6]

[Abi Waqas]

thank you for the reponse :)

I have found someother solution for that