i want to keep calculating better values of root iteratively until either the max number of iteration is used or the error is less than the tolerance and then display the values using the switch statement.i think somethin is wrong in my while loop.

k=1;

   e=-1*((x(k+1)-x(k))/x(k+1))*100;

while e > tol && k==x_max;

e=-1*((x(k+1)-x(k))/x(k+1))*100;

k=k+1;

end

switch e
    case e< tol

disp('Success!The result is %.4f',e)

case  e<0

disp('The number was negative.')

      otherwise
          disp('Maximum number of iteration used.')

end

[Rena Berman]

(Answers Dev) Restored question.

Answer 1

[Thorsten]

 k_max = 100; % sample value, maximum number of iterations
 :
 while e > tol & k <= k_max
 :

[anonymous19]

i just ran it and the while loop is fine but it wont display my results using the switch statement.

[Thorsten]

The switch does not work because you compare e to (e<tol) or (e<0), both are logical values (0 or 1). Instead, use

if e < tol
  disp('Success!The result is %.4f',e)
elseif  e < 0
   disp('The number was negative.')
else
   disp('Maximum number of iteration used.')
end

[Walter Roberson]

switch true
   case e < tol
     disp('Success!The result is %.4f',e);
   case e < 0
     disp('The number was negative.')
   otherwise
     disp('Maximum number of iteration used.')
 end