Changing a matrix into a binary matrix

I have a large matrix in which i need to turn it into a binary matrix form. There are criteria in which each value needs to meet. If a value in the matrix is greater than the second deviation of the matrix it is assigned a 1, and if the value is less than or equal to the standard deviation it shall be given a value of 0. Does anybody know how to translate the if statement around the matrix and then change the value to either a 1 or 0. Any replies would be grateful.

Answer 1

[Star Strider]

This is how I would do it:

M = randn(10);                          % Matrix
M0 = M - mean(M(:));                    % Subtract Mean
Mstd = std(M0(:));                      % Standard Deviation of ‘M’
Mgt = M0 > Mstd;                        % Greater Than 1 S.D.

If you want it to be symmetrical, that is to set all values either >1 S.D. or <-1 S.D. to 1, do this:

M = randn(10) + 1;                      % Matrix
M0 = M - mean(M(:));                    % Subtract Mean
Mstd = std(M0(:));                      % Standard Deviation of ‘M’
Mgt = (M0 > Mstd) | (M0 < -Mstd);       % Greater Than 1 S.D. -OR- Less Than -1 S.D.