Fastest way to determine if a character index is a carriage return (\n)?

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Hi all.
1.15 seconds per 100,000 iterations:
if regexp(text(index),'[\n]','once')
y = 1;
else
y = 0;
end
1.25 seconds per 100,000 iterations:
ret = regexp(text(index),'[\n]');
if any(ret==index)
y = 1;
else
y = 0;
end
I would think there is a faster way, but I have yet to find it. Any Suggestions??
Thanks so Much!
Will
EDIT: I acknowledge there are more than 1 type of carriage return, for simplicity lets assume the text only has one type.
  2 Comments
Guillaume
Guillaume on 29 Jul 2016
Edited: Guillaume on 29 Jul 2016
AS per dpb answer, for finding a single character, direct comparison is going to be A LOT faster than involving a regular expression engine. I just wanted to comment on the regular expression.
[] is used in regular expressions to group several characters together (i.e. match any of the characters within the brackets). When there's only one character to match, the brackets serve no purpose, so
regexp(text, '\n', once)
would have worked just as well and would avoid wondering if the fact that there's only one character in the class is a bug or not.
I doubt it would make any difference to speed.

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Accepted Answer

dpb
dpb on 29 Jul 2016
y=any(text(index)==char(10));
  4 Comments
dpb
dpb on 29 Jul 2016
Edited: dpb on 29 Jul 2016
No problem, glad to help where can... :)
Another note is that if performance is the issue, as written passing the index into the function it probably actually would make more sense to simply do the test inline instead of using the function.

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More Answers (1)

Image Analyst
Image Analyst on 29 Jul 2016
I'm not sure what 15 is (it's a "shift in" character) but, like Stephen says carriage return is 13. And you don't need char(). So it would be
crIndexes = yourText == 13;
Here's a full demo showing lots of possible ways that new lines show up in the ASCII bytes:
yourText = sprintf('abc\n def \r hij \r\n klm \n\r theEnd')
crIndexes = yourText == 13 % Find all CR
lfIndexes = yourText == 10 % Find all LF
% Find pairings with strfind():
crLF_location = strfind(yourText, [13, 10])
lfCR_location = strfind(yourText, [10, 13])
  1 Comment
dpb
dpb on 29 Jul 2016
..."you don't need char()..."
Good catch, IA; I'll make the correction. Normally I don't do that, not sure why did this go-'round... :(

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