Replacing a portion of matrix in cell with value of another matrix

Hi, I have some problems in creating:

A cell eg : A = {[100x70double], [50x120], [7x20]} However, I want to replace the value of a portion from each array of cell A from another array. The replacement size is [2x3] where the value is B= [1.1 1.2 1.3;2.1 2.2 2.3;]

I'm currently trying this:

 % code
  for i = 1:size(A,1)
    for j = 1:size(A,2)
            A {i,j} (1:4,1:7) = B

    end
end

But i've got "Subscripted assignment dimension mismatch" error.

Thank you in advance.

Answer 1

[KSSV]

It should be:

for i = 1:size(A,1)
    for j = 1:size(A,2)
        A {i,j} (1:2,1:3) = B;
    end
end

The indices which you specify shall cover 2X3. 1:4,1:7 makes a 4x7 matrix.

[bam]

Than you Dr. Siva Srinivas Kolukula. However, the same error still exist.

[KSSV]

That code works perfect in my pc. Copy your full code here what you have tried?

clc; clear al; 
A = {rand(100,70), rand(50,120), rand(7,20)} ;   % a random data 
B= [1.1 1.2 1.3;2.1 2.2 2.3];
% code
for i = 1:size(A,1)
    for j = 1:size(A,2)
        A {i,j} (1:2,1:3) = B;
    end
end

[bam]

Yes. I have tried your code. It works really well. It was my mistakes since i'm wrongly declare the dimension of array B.Thank you dr.