averaging repeated neighbouring values on logical?

My logical array:

ans =

    1×79 logical array

    Columns 1 through 26

     1   0   0   0   0   0   0   0   0   0   0   0   0   1   0   1   0   0   0   0   0   0   0   0   0   0

    Columns 27 through 52

     0   0   0   0   0   0   1   0   0   0   0   1   0   0   0   0   0   0   0   0   0   0   0   0   0   0

    Columns 53 through 78

     0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   0   1   1   0   0   0   0   0   0   0

    Column 79

     0

For the values with 1 and 1 (adjacent to each other) are repeated, so I want to average with next/previous closest 0 values.

I currently have the code to average them:

if sum(diff(outliers) == 1) == 1
    answ = input('Several consecutive volumes are seen as outliers. Do you want to ''repair'' anyway? [y/n] ','s');
        if strcmpi(answ,'y')

              for im=1:length(outliers)
            bad_slices = r(:,outliers(im))<(M-k*value);
            Image(:,:,bad_slices,outliers(im)) = (Image(:,:,bad_slices,outliers(im)-1) + ...
                Image(:,:,bad_slices,outliers(im)+1))/2;
            end

But it does not work. Thanks in advance!

[Sindhu Priya]

Can you please tell,whether your logical array displayed in the question is the 'outliers' used in the code snippet?

If the 1's are adjacent , can you explain clearly with what values you want to replace?

Answer 1

[Walter Roberson]

You have a logical array. The only two values that can exist in it are 0 and 1. 1/2 or 2/3 or whatever cannot exist in it, and will be converted to 1 for all non-zero numeric values.

If you need any other numeric values then you will need to convert the array to double