How to transform the entry in the vector in ascending and descending order after few points?

Hi,

This question may sound silly but I really need help.

I have a vector

X=[1 1 1 1 1 10 1 1 1 1 1 1 1 1 1];

and i wish to transform this vector X to

X_new=[9 9 9 9 9 10 10 10 10 10 11 11 11 11 11];

by using the information and position of the entry 10 in vector X.

May I know how to construct the new vector X_new?

Thanks in advance.

[James Tursa]

What are the rules for creating X_new? In your example you have five 9's, five 10's, and five 11's. What would be the result if the 10 were in the 1st or 2nd or 12th or last place, for instance? How is this affected by the number of elements of X?

[Ming Gui]

Hi,

Sorry for being unclear... If the 10 is in 3rd place, I need 5 10's follow by 5 11's follow by 5 12's until end of number of sample X. The previous 1st and 2nd still need to be 9s.

Thank you for your help :)

[Birdman]

Check my answer.

[Ming Gui]

Hi Mr Çevikalp Sütunç,

Thanks for your answer. Unfortunately, the code can only fit the current X. What if I increase the number of sample in X? Let say

X=[1 1 1 1 1 10 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1];

The pattern remain the same, the new vector

X_new=[9 9 9 9 9 10 10 10 10 10 11 11 11 11 11 12 12 12 12 12 13 13 13 13 13];

How do I have a universal code to fit for different sample?

Thanks a lot.

Answer 1

[Andrei Bobrov]

ii = find(X~=1)-1;
Y = zeros(size(X));
Y(1:ii:numel(X)) = 1;
out = X(ii + 1) + cumsum(Y) - 2;

or

ii = find(X~=1)-1;
out = ceil((1:numel(x))/ii) + X(ii+1) - 2;

[Ming Gui]

Hey this is almost what i need. I just need slight modification and it achieve my objective... thanks alot...

Answer 2

[Birdman]

clear;clc;X=[1 1 1 1 1 10 1 1 1 1 1 1 1 1 1];cnt=0;
for i=1:1:length(X)
    if(X(i)==10 && cnt==0)
        for j=1:1:i-1
            X(j)=10-1;
        end
        cnt=1;
    end
    if(cnt==1)
        if(i<=10)
            X(i)=10;
        end
    end
    if(i>10)
        X(i)=11;
    end
end