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## list the result of the index values in ranges

Asked by Nasser Ramsis

### Nasser Ramsis (view profile)

on 22 Oct 2017
Latest activity Commented on by Nasser Ramsis

### Nasser Ramsis (view profile)

on 23 Oct 2017
Accepted Answer by Jos (10584)

### Jos (10584) (view profile)

Hello,
I have an array that is populated with the values 1,2 or 3.
a = [1 1 2 2 3 3 2 2 1 1];
and I want to list the ranges of each value. The find function retrieves the index to each number which is great.
[col1] = find(a==1)
[col2] = find(a==2)
[col3] = find(a==3)
but is there a function or some logic i can use to list col1, col2, and col3 as ranges? as in col1 = 1-2 and 9-10 and col2 = 3-4 and 7-8 etc etc.
I appreciate any ideas or help.
Thank you in advance!

Jos (10584)

### Jos (10584) (view profile)

on 22 Oct 2017
You might want to search for run length encoding.

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## 2 Answers

### Jos (10584) (view profile)

Answer by Jos (10584)

### Jos (10584) (view profile)

on 22 Oct 2017
Accepted Answer

A = [1 1 2 2 3 3 2 2 1 1];
X = arrayfun(@(k) find(A==k),1:3,'un',0) ;
Y = cellfun(@(v) [v([true diff(v) > 1]) ; v([diff(v) > 1 true])]', X,'un',0) ;
% Y{k} contains the start indices (1st column) and end indices (2nd column) for a sequence of the value k in A

Nasser Ramsis

### Nasser Ramsis (view profile)

on 23 Oct 2017
Thank you.
This is working great in 1 of my functions but this other function is giving me this message:
Index exceeds matrix dimensions.
Error in @(v)[v([true,diff(v)>1]);v([diff(v)>1,true])]'
Error in test (line 60) Y = cellfun(@(v) [v([true diff(v) > 1]) ; v([diff(v) > 1 true])]', X,'un',0) ;
Any ideas? do you want to see the entire code?

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### Andrei Bobrov (view profile)

Answer by Andrei Bobrov

### Andrei Bobrov (view profile)

on 22 Oct 2017
Edited by Andrei Bobrov

### Andrei Bobrov (view profile)

on 22 Oct 2017

a = [1 1 2 2 3 3 3 2 2 1 1];
l = diff([0,a(:)'])~=0;
b = [strfind(l,[1 0]);strfind([l,1],[0 1])]';
out = accumarray(a(l)',1:size(b,1),[],@(x){sortrows(b(x,:))});

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