quick itteration

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Ahmed Hassaan
Ahmed Hassaan on 25 Apr 2012
Hello ,
I want a better speed in operating my code ,if i did enter a large number of points like 10000 it will operate in 10 mins or more and my processor is good enough ,this code is plotting points in a uniform shape like rectangular and randomly with different x and y , thanks for attention.
%%
RN=input('Enter number of points =');
U1=[];U2=[];
for i=1:RN
xa=-L/2+L*rand(1,1)+0.2*rand(1,1)-.4;
ya=-N/2+N*rand(1,1)+0.2*rand(1,1)-.4;
xra(i)=xa;yra(i)=ya; z=[xra(i) yra(i)];
sub1=z(1);sub2=z(2);U1=[U1;sub1];U2=[U2;sub2];
USERS=[U1 U2];
figure(1)
plot(xra(i),yra(i),'k.');hold on
end

Accepted Answer

Daniel Shub
Daniel Shub on 25 Apr 2012
The best thing to do would be to move the plotting outside the loop:
...
end
figure(1);
plot(xra,yra,'k.');

More Answers (2)

Junaid
Junaid on 25 Apr 2012
Though your code requires cleaning but this code will generate exact output you are required. In your code there are many variables which are not required.
RN=input('Enter number of points =');
L=input('Enter the length x =');
N=input('Enter the length y =');
U1=[];U2=[];
xa = -L/2+L*rand(RN,1)+0.2*rand(RN,1)-.4;
ya = -N/2+N*rand(RN,1)+0.2*rand(RN,1)-.4;
xra=xa;yra=ya; z=[xra yra];
sub1=z(:,1);sub2=z(:,2);U1=[U1;sub1];U2=[U2;sub2];
USERS=[U1 U2];
figure(1)
plot(xra,yra,'k.');

Junaid
Junaid on 25 Apr 2012
I guess this can be done in one line without using for loop, and second line for plot. Could you tell us about L, N and other varibales you are using in side loop
  3 Comments
Ahmed Hassaan
Ahmed Hassaan on 25 Apr 2012
L=input('Enter the length x =');
N=input('Enter the length y =');
Daniel Shub
Daniel Shub on 25 Apr 2012
Without having timed it, my guess is the time improvement from complete vectorization will be small compared to the use of a single plot.

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