if any a can be index?

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Da'Moon
Da'Moon on 5 Dec 2017
Edited: Da'Moon on 5 Dec 2017
A(n)=1;

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Accepted Answer

Image Analyst
Image Analyst on 5 Dec 2017
Perhaps this:
VV=8;
v=length(y);
n=0;
for k=1:VV:length(y)
n = n + 1;
if any(y(k:k+8))
A(n)=1;
else
A(n)=0;
end
end
By the way, are you sure you don't want k:(k+7) instead of k:k+8?
  2 Comments
Da'Moon
Da'Moon on 5 Dec 2017
you are correct!
Da'Moon
Da'Moon on 5 Dec 2017
thank you it seems its working now!

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