For and Break Stuck

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Berkcan Oz
Berkcan Oz on 20 Mar 2018
Edited: Walter Roberson on 21 Mar 2018
Hi everybody. I wrote a code but something is going wrong, I need at that point.
I need to stop the code at the gain of 0.5 and I need to take the values that I need as P and D. But The code does not do what I need. It always work around i = 65 and j = 65. What is the error ?
clear all; clc;
Kp = -10:0.31:10;
Kd = -10:0.31:10;
% n = [Kd Kp];
% d = [(1+Kd) (Kp+1)];
%
% [r,p,k] = residue(n,d);
A = zeros(length(Kp), length(Kd));
for i = 1:length(Kp)
for j = 1:length(Kd)
n = [Kd(j) Kp(i)];
d = [(1+Kd(j)) (Kp(i)+1)];
[r,p,k] = residue(n,d);
S = sum(r);
TF = tf(n,d);
[z, gain] = zero(TF);
if gain == 0.5
break;
end
% if S<0.6 && S>0.4
% A(i,j) = 1;
% else
% A(i,j) = 0;
% end
end
end

Answers (1)

James Tursa
James Tursa on 20 Mar 2018
It is often better to use tolerances for floating point comparisons, unless you wrote the underlying code and you know that the result must be exactly 0.5. So this test
if gain == 0.5
should probably look something like this instead
if abs(gain - 0.5) < tol % for some appropriate value of tol
  5 Comments
Stephen23
Stephen23 on 21 Mar 2018
You could start with tol=1e-5;
Berkcan Oz
Berkcan Oz on 21 Mar 2018
Edited: Walter Roberson on 21 Mar 2018
Now, I did this but this give me a system that starts at gain almost 0.5 and goes 1. I need to make it from 0 to 0.5. Not from 0.5 to 1. What should I do ?
clear all; clc;
Kp = -10:0.31:10;
Kd = -10:0.31:10;
tol = 1e-5;
A = zeros(length(Kp), length(Kd));
for i = 1:length(Kp)
for j = 1:length(Kd)
n = [Kd(j) Kp(i)];
d = [(1+Kd(j)) (Kp(i)+1)];
[r,p,k] = residue(n,d);
S = sum(r);
TF = tf(n,d);
[z, gain] = zero(TF);
if gain <0.6 && gain>0.4
break;
end
end
end
sys = tf(n,d)
step(sys);
grid;

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