Asked by Praveen Pawar
on 18 May 2018 at 11:29

Users are uniformly distributed in the circular area and base station is at the center. If the distance is varied then their corresponding rate should also be different. Here is the code, I am getting the approximate same rate for all users. Where is the mistake in my code? any suggestion is very thankful.

n_users=10;%no. of users N0dbm=-124; %%% noise power N0 = 10^((N0dbm-30)/10); P_MBS=20;%Power in watt MBS_XY = [0 0]; r_MBS=100; alpha=0.3; %bandwidth allocation FREQ = 2.15; angle_users = 2*pi*rand(n_users,1); r_users = r_MBS*sqrt(rand(n_users,1)); %x and y coordinate of users X_users = r_users.*cos(angle_users)+ MBS_XY(1); Y_users = r_users.*sin(angle_users)+ MBS_XY(2); XY_users=X_users + 1i.*Y_users; MBS_XY = MBS_XY(1)+1i*MBS_XY(2); %%% %% Calculate channel gain dist_users = abs(XY_users-MBS_XY); path_loss = 10*alpha*log10(dist_users) + 27.3 + 26*log10(FREQ); shadowing = 4*ones(size(dist_users)); shadowing = shadowing.*randn(size(shadowing)); %%% sub_power_array = 10.^((shadowing-path_loss)./10); % caculate shadowing %%% size_h = size(sub_power_array); % caculate h h = sqrt(0.5)*randn(size_h)+sqrt(0.5)*randn(size_h)*1j; % final power array channel_gain = (abs(h)).^2.*sub_power_array; G_MBS = channel_gain; %%%% %% Rate R_MBS = log2(1+(P_MBS.*G_MBS)./N0); %%Rate or shannon capacity

Answer by KALYAN ACHARJYA
on 18 May 2018 at 12:05

Edited by KALYAN ACHARJYA
on 18 May 2018 at 12:08

The output is not same, where you got the same results if you vary the n_user

KALYAN ACHARJYA
on 18 May 2018 at 12:49

??

Praveen Pawar
on 18 May 2018 at 13:03

KALYAN ACHARJYA
on 18 May 2018 at 13:26

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