## How can I search data for various conditions and if conditions are met (more than once) assign variables?

### Trude Mashburn (view profile)

on 11 Jun 2018
Latest activity Edited by Trude Mashburn

### Trude Mashburn (view profile)

on 12 Jun 2018
The Details: I have a matrix of input data that I read into a script. The matrix is large e.g 70000 for row and 3 for column. Input = matrix(70000, 3) Column 1 is time Column 2 is A Colum 3 is B
I have a script set up (see below). I need the script to read the data file and check each row of Column 2 and 3 for a condition. If it meets that condition I set the variable ACond1, ACond2, BCond1 and/or BCond2 equal to the time that is associated with that Condition. The problem: There are multiple occurrences (times) that ACond1, ACond2, BCond1 and/or BCond2 and of these only select occurrences will be ACond1_e, ACond2_e, BCond1_e, and BCond2_e.
A working script with the example data shown below would yield the following: ACond1 (1) = 2.00 ACond1(2) = 17.00 ACond1(m) = ACond2(1) = 6.00 ACond2(2) = 22.00 ACond2(m) BCond1(1)= 8.00 BCond1(2) = 24.00 BCond1(m) BCond2(1) = 14.00 BCond2(2) = 30.00 BCond2(m)
Typically ACond1 would occur before ACond2 and BCond1 would occur before BCond2 and In addition the ACondition would occur before BCondition.
*********************** Example of the data is as follows: time = [1.00, 2.00, 3.00, 4.00, 5.00, 6.00, 7.00, 8.00, 9.00, 10.0, 11.0, 12.0, 13.0, 14.0, 15.0, 16.0,17, 18, 19, 20, 21, 22, 23,24, 25, 26, 27, 28, 29, 30, 31,32];
A = [2, 3, 3, 3, 3, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 2, 3, 3, 3, 3, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7];
B = [1, 1, 1, 1, 1, 1, 1, 3, 3, 3, 3, 3, 3, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 3, 3, 3, 3, 3, 3, 2, 2, 2];
time = data(:,1); A = data(:,2); B = data(:,3);
% Flags for Events. % A = 3; % A in condition 1 % A = 6; % A in condition 2 % B = 3; % B in Condition 2 % B = 2; % B in Condition 1
% Set up (initialize) counters for the If Statements below c = 0; d = 0; e = 0; f = 0; % % Set up zero vectors ACond1 = zeros(size(c)); ACond2 = zeros(size(d)); BCond1 = zeros(size(e)); BCond2 = zeros(size(f));
% Initializing some variables n = 1; BCond2 = 0;
% If statements search each row of input (time, A and B and % identify the time for the first occurrence of ACond1, ACond2, BCond1 and BCond2
for i = 1:max(size(time)) if A(i) == 3 c = c + 1; for p = 1:max(size(c)) ACond1(1,c) = time(i); end; ACond1_e = min(ACond1()); end; if A(i) == 6 d = d + 1; for q = 1:max(size(d)) ACond2(1,d) = time(i); end; ACond2_e = min(ACond2()); end; if B(i) == 3 e = e + 1; for r = 1:max(size(e)) BCond1(1,e) = time(i); end; BCond1_e = min(BCond1()); end; if B(i) == 2 f = f + 1; for s = 1:max(size(f)) BCond2(1,f) = time(i); end; BCond2_e = min(BCond2()); end; if (time(i) > BCond2) n = n + 1; end; end; i = i - 1; end

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on 11 Jun 2018