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I can I do logical indexing on a column

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Engdaw Chane
Engdaw Chane on 20 Jul 2018
Commented: Engdaw Chane on 20 Jul 2018
Hello everyone,
I have a column which is 840 in length. It contains value s from -12 to 12. I need only values < -8 and >8. I need to keep the length 840. I tried the following. but it says " 0x1 empty double column vector".
v = zeros (size (data)); % Pre-allocate!
v=data(data <-8 & data>8)
thank you for helping.
Chane

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Accepted Answer

Birdman
Birdman on 20 Jul 2018
Edited: Birdman on 20 Jul 2018
Is it possible for a value to be smaller than -8 and greater than 8 at the same time? Check your logical operator. You need OR operator instead of AND.
v=data(data <-8 | data>8)
You can not keep the length same. If you want that, fill the other values with a specific value, like zero.

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Engdaw Chane
Engdaw Chane on 20 Jul 2018
Birdman and Guillaume, Thank you for your swift replay. the solution works fine.I am working on a time-series data. so I need to keep the values to the month they belong. the remaining months can be zero. but how can fill the zeros?
Guillaume
Guillaume on 20 Jul 2018
Well, if you want to replace values less than absolute 8 by 0, then:
v(abs(v) < 8) = 0;
You may want <= instead of <
Engdaw Chane
Engdaw Chane on 20 Jul 2018
Birdman and Guillaume, Thank you!

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