MATLAB Answers

Inverse Fourier Transformation with a function in the exponent

1 view (last 30 days)
Shoaibur Rahman
Shoaibur Rahman on 1 Aug 2018
Edited: Shoaibur Rahman on 1 Aug 2018
I have a signal x[n] with it's Fourier Transform X[k]. I want a frequency-warped signal (x_warp[n]) by taking the inverse Fourier of X[k], with a warping function fun. I know the fun will be somehow incorporated to the exponent of original inverse Fourier e^(j*2*pi*k*n/N)
So far, I have the following code:
x_hat = 1/N * X(1:N/2+1) * exp(1j*fun'/Fs*2*pi*(0:N-1))
x_warp = 2*real(x_hat)
Fs=Sampling frequency. Could you please tell me if the expression in the exponent is correct or not? I.E. what will be exp(???) in the above code?
Thanks in advance!


Sign in to comment.

Answers (0)

Sign in to answer this question.