hey guys o have question about log ...

if i have function = log5(X) and he wants the taaylor how can i deal with the log5(x)

[Stephen23]

Ali Alramadan's "Answer" moved here:

my code was

syms x;
f=log5(x);
t3=taylor(f,x,0,'order',4)

but it always gives me error

[Steven Lord]

What is the body of the log5 function? There is no function by that name in any MathWorks product as far as I am aware (and searching the website didn't find any such functions.)

What is the full text (everything in red) of the error message you received when you ran that code?

[James Tursa]

log base 5?

Answer 1

[the cyclist]

You can get the base-5 log of a number x as follows

log(x)/log(5)

A simple explanation of why this works can be found here.

Then, you can simply use the Taylor expansion of log(x).

[James Tursa]

... in which case he will get a different error!