# Create a logical vector

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PAK on 2 Aug 2018
Commented: PAK on 3 Aug 2018
Hi All,
I have a cell array, where each cell in the first row contains a double of various lengths. Each double corresponds to sample numbers where a spike occurs (from a neuron - variable called cluster_split). I also have created an array of 0's the length of signal I am interested in (variable called LFP). I would like to index across each double (i.e.: cluster_split{1,1}) and create a logical vector of 1's and 0's.
For example, if in cluster_split{1,1} there is a value equal to 2502 (corresponding to sample 2502 in the LFP vector), then Matlab would output a 1 to the LFP array. I would like to create a separate "LFP" file for every double in the cluster_split cell array.
Thanks in advance for the help!
PK

Adam Danz on 2 Aug 2018
Edited: Adam Danz on 2 Aug 2018
Does this help?
LFP = false(1, 3000);
LFP(2500) = true;
If LFP is at millisecond resolution and a spike occurs at 2500 milliseconds, you'll see a 1 in position 2500. Since I used true/false the vector is logical.

PAK on 3 Aug 2018
Cluster_class is a cell array, with each column in the first row containing another array. Does your comment still apply? Thanks! PK
Adam Danz on 3 Aug 2018
Does each array cluster_class{n} have the same size? In other words, are all cell arrays stored in cluster_class the same length? If so, this code can be simplified.
In any case, what is the value of 'clusters'? I think what you want is something like this
LFP = false(length(cluster_class), test);
for i = 1:length(cluster_class)
LFP(cluster_class{i}) = true;
end
PAK on 3 Aug 2018
Each array is not the same size. The value of 'clusters' is [1,2,3,4,5,6,7,8]. Essentially the row length of cluster_class{n}. The following code below works!
LFP_size = size(data,2);
for i = clusters
LFP(i, :) = false(1, LFP_size);
LFP(i,cluster_split_recalled_samples{i}) = true;
end