Shifting column of a matrix with maximum sum to the right?

After using a for loop to calculate the sum in each column of the matrix; how can I move the column with largest sum to the right of the matrix? I used:

  for i = i: b
      sum_col(i)=sum(B(:, i));
  end
  [I,M]=max(sum_col);
  C=A(:,2);
  A(:,2)=A(:,I);
  A(:,I)=C;

- After using a for loop to calculate the sum

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Stephen23]

>> M = randi(9,4,7) % fake data
M =
    9    5    5    1    6    9    4
    3    5    8    9    1    5    2
    2    1    7    8    7    4    9
    7    2    8    5    2    3    5
>> sum(M,1) % sum of each column
ans =
   21   13   28   23   16   21   20
>> [~,X] = max(sum(M,1)); % max column sum.
>> M = M(:,[1:X-1,X+1:end,X]) % rearrange
M =
    9    5    1    6    9    4    5
    3    5    9    1    5    2    8
    2    1    8    7    4    9    7
    7    2    5    2    3    5    8
>> sum(M,1) % check
ans =
   21   13   23   16   21   20   28

Answer 2

[madhan ravi]

no need of loops and no need to rearrange - JUST SWAP!

>> a=rand(4)
   [~,X]=(max((sum(a))))
   a(:,[X end])=a(:,[end X])

a =

      0.2501    0.5916    0.5017    0.6008
      0.9277    0.2033    0.6508    0.1125
      0.0686    0.6359    0.7960    0.5158
      0.2994    0.7984    0.2334    0.8378

X =

       2

a =

      0.2501    0.6008    0.5017    0.5916
      0.9277    0.1125    0.6508    0.2033
      0.0686    0.5158    0.7960    0.6359
      0.2994    0.8378    0.2334    0.7984

>>

[Rik]

Nor of find (use second output of max)

[madhan ravi]

Thank you @Rik much appreciated learning a lot from you :)

[Stephen23]

Note that this changes the order of the other columns, which may or may not be acceptable.

[madhan ravi]

Thank you @stephen didn't notice it