Asked by antonet
on 4 Jul 2012

I have 2 cell matrices R and W and I want to check if they contain the same elements. Specifically, I want to compare R which is obtained from

[N,T,R] = xlsread( filename); %

with another matrix W.Both matrices are cell matrices and can also contain NaN entries.

My goal: If my calculations are correct then

kk=W(7 ,3:end); should contain the same elements with

zz1=R(7,3:end);

or zz2=R(8,3:end);

So to test this I do something like

if zz==xx1 | zz== xx2

'OK' else 'Not OK' EndThe problem is that

zz==xx1

??? Undefined function or method 'eq' for input arguments of type 'cell'.

So I use cell2mat(zz)==cell2mat(xx1) and it works.

But if zz and xx1 contain NaN then for some reason I cannot use the cell2mat() approach

I am looking for a general approach that will enable me to do that comparison whether I have NaN and numbers or only numbers’

thanks

*No products are associated with this question.*

Answer by Andrei Bobrov
on 5 Jul 2012

Edited by Andrei Bobrov
on 5 Jul 2012

Accepted Answer

variant of comparison cell arrays (edit)

A = {... [84] [ 93] [ 109] [99] [NaN] [ 62] [29] [123] 'dgdgdg'}; B = {... [84] [ 93] [ 109] [99] [NaN] [ 62] [29] [123] 'dgdgdg'};

A1=A; B1=B; A1(cellfun(@(x)all(isnan(x)),A)) = {0}; B1(cellfun(@(x)all(isnan(x)),B)) = {0}; out = isequal(A1,B1);

Andrei Bobrov
on 5 Jul 2012

yas, thank.

antonet
on 5 Jul 2012

can i omit

A1=A;

B1=B;

so as to simlpy have

A = {... [84] [ 93] [ 109] [99] [NaN] [ 62] [29] [123] 'dgdgdg'}; B = {... [84] [ 93] [ 109] [99] [NaN] [ 62] [29] [123] 'dgdgdg'};

A(cellfun(@(x)all(isnan(x)),A)) = {0};

B(cellfun(@(x)all(isnan(x)),B)) = {0};

out = isequal(A,B)

thanks

Andrei Bobrov
on 5 Jul 2012

Hi Antonet! Thank you for "Accepted answer", but I mean that Jan's answer better.

Log in to comment.

Answer by Jan Simon
on 5 Jul 2012

C1 = {'String1', 23, -17, NaN, 1:29); C2 = {'String2', 24, -17.3, 21, 1:30); C3 = {'String1', 23, -17, NaN, 1:29);

% |C1==C2| fails! isequalwithequalnans(C1, C2) isequalwithequalnans(C1, C3)

I cannot test this currently. When NaNs should be assumed to be different, `isequal` would do it.

Andrei Bobrov
on 5 Jul 2012

+1

Teja Muppirala
on 5 Jul 2012

antonet
on 5 Jul 2012

what is +1 means?

Log in to comment.

Answer by Kevin Claytor
on 4 Jul 2012

My guess from searching the help docs for 'cell' gives;

m = cell2mat(c) converts a multidimensional cell array c with contents of the same data type into a single matrix, m.

antonet
on 4 Jul 2012

I forgot to tell you that it contains also string variables and if i type

cell2mat(c)

i get :

Error using cell2mat (line 46) All contents of the input cell array must be of the same data type.

Walter Roberson
on 5 Jul 2012

Jan Simon
on 5 Jul 2012

@antonet: Please provide the necessary information in the original question, because readers in this forum will read it at first. Therefore you can **edit** the question.

The code you have posted is hard to read. Please read the instructions about code formatting again.

Log in to comment.

Related Content

MATLAB and Simulink resources for Arduino, LEGO, and Raspberry Pi

Learn moreOpportunities for recent engineering grads.

Apply Today
## 1 Comment

## Jan Simon (view profile)

Direct link to this comment:https://www.mathworks.com/matlabcentral/answers/42758-comparing-matices-that-contain-numbers-and-nans#comment_87885

@Readers: It seems like anonet wants to compare cells, which contain numerical and string values.

Log in to comment.