cellfun in new version

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ori yungrise
ori yungrise on 26 Nov 2018
Commented: ori yungrise on 27 Nov 2018
I am trying to update an old code.
The code has many lines with "cellfun" function and i use anonymous functions.
It worked well at R2012b version but it dowsnt work at R2018a version.
examples:
  • cellfun(@(x) logical(exist(x,'var')), handles.Names); % . The names in it are variables that exist in the workspace.
  • cellfun(@(x) eval(['handles.' x ' =cell(size(Size_Parameter));']), handles.Names);
  • cellfun(@(x) save([FullFileName],'-struct','handles',x,'-append'),handles.Names);
handles.Names is cell array in my GUI.
All these work well in R2012b but not in R2018a.
I will be glad to get some help. Do i have to replace all these command lines into loops?
  6 Comments
Walter Roberson
Walter Roberson on 27 Nov 2018
for ii=1:numel(handles.Names)
handles.(handles.Names{ii}) = cell(size(Size_Parameter));
end
In the case where the handles struct starts out empty, then there is another way to do it in vectorized form involving cell2struct(), or a different way involving struct() and structfun(). There are probably other ways as well for that situation. They do not, however, apply for the case where handles already has content.
ori yungrise
ori yungrise on 27 Nov 2018
Thank you, this is great!

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Accepted Answer

Walter Roberson
Walter Roberson on 26 Nov 2018
cellfun(@(x) logical(exist(x,'var')), handles.Names)
The exist() is going to be executed in the context of a function. It will test the existence of the given name as a variable in the workspace of the function, then as a parameter to the function (second), then as a shared variable in a nested function, then as a global variable that has been declared as global in the function. But the function context that the exist() is being executed in is the anonymous function, which has no saved variables and has one parameter named 'x' and is not a nested function and has no global declared in it. The only variable name that exists will therefore be 'x'. If there happened to be a 'x' in handles.Names then that one will succeed and all others will fail.
In order for this anonymous function to do anything more useful it would need to use evalin('caller')
If you do not need to know about parameters or shared variables, then you could instead
ismember(handles.Names, who())
  1 Comment
ori yungrise
ori yungrise on 27 Nov 2018
Edited: ori yungrise on 27 Nov 2018
Hi Walter,
I wil use: "ismember(handles.Names, who())" and then "logical".
Any ideas about the other two comman lines?
Thank you!

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