How to apply a condition on array?

  a  = [1 2 3 4 5]
x(a) = [15 20 45 25 30]
b = [6 7 8 9 10]
x(b) = [20 25 30 15 15]
t=40

the below array ab is a random permutation of a and b elemnts and then zeros are inserted.

ab = 5     2     6     0     4     9     8     7     0     1    10     0     3

I want to apply this condition on the between zeros of array ab:

the condition is that if the values of the corresponding values of x(a) and x(b) for a and b elemnts between zeros are greater than t, in this case add a penalty of 100. Then acummulate the total penalty of these between zeros values

This condition includ the mix case of 1-5 and 6-10 between zeros and the individaul case like 3 at the end of ab.

[Jan]

I do not understand the question. Please post, what you expect as output for these input data.

[Image Analyst]

There is a zero at ab index 12, yet x doesn't have an index 12 - it's only 10 long - so what is your plan there?

[Hajem Daham]

Sorry for confusing, let me explain in more details.

take the first between zeros elements 5 2 6 the x(a)'s values for 5 is 30 and for 2 is 20, the sum of x(a) for 5 and 2 is 50 which is largere than 40, so in this case there is a 100 penalty. The x(b) for 6 is 20 which is less than 40 so the penalty is 0, the total penalty for the 5 2 6 is 100. Similarly take the second between zeros elements which are 4 9 8 7, the x(a) value for element 4 is 25 which is less than 40 so the penalty is 0, while the x(b)'s values for 9 8 7 are 15 30 25= 70 which is large than 40 so the penalty for elemnts 9 8 7 is 100 and the total penalty for the 4 9 8 7 is 100. Similarly for other between zeros. Finaly I want the total sum of penalty for all all between zeros elemnts. A loop should be made for this process.

Hope it is clear now.

[Hajem Daham]

Image Analyst, thereis no x(a) or x(b) for the zeros in ab, so please ignore the zeros in ab just focus on values between zeros.