Vector output from a function
2 views (last 30 days)
Show older comments
Working on a projectile motion problem. I am trying to get x_dist and y_height vectors as outputs from my function so that I can then graph them. When I run my function it tells me that the variable x_dist does not exist even though it is in my function. Any help would be appreciated!
function [x_dist,y_height]=projectile(V_int,theta)
dt=1; %seconds
w=3; %kg
k=0.32;
g=9.81; %m/s^2
i=1;
y=0;
while y>0
a_y(i)=w*g-V_int*k;
a_x(i)=-V_int*k;
v_y(i)=(V_int*sin(theta))+(a_y(i)*dt);
v_x(i)=(V_int*cos(theta))+(a_x(i)*dt);
x_dist(i)=(V_int-v_x(i))/1;
y_height(i)=(V_int-v_y(i))/1;
V_int=v_x(i);
V_int=v_y(i);
i=i+1;
dt=dt+1;
end
pause(0.5);
comet(x_dist,y_height);
end
0 Comments
Accepted Answer
Stephan
on 26 Mar 2019
Edited: Stephan
on 26 Mar 2019
Hi,
you set y=0. one line later you start a while loop, that is valid as long as y>0. This can not work. For this reason xdist is not there, because the while loop stopps the same moment it starts. xdist is defined inside the while loop.
Best regards
Stephan
0 Comments
More Answers (1)
Walter Roberson
on 26 Mar 2019
Edited: Walter Roberson
on 26 Mar 2019
You initialize y = 0. You have while y>0 . But 0>0 is false, so the body of your while loop is never done, and nothing was ever assigned to x_dist or y_height.
Note: you also do not assign to y in the loop, so if the loop did ever get started, then it would not stop.
0 Comments
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!