Vpasolve higher polynomials does not give a real solution

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equation_clean = poly2sym(p,t) %the equation of the polynomial interpolation
yvalues = polyval(p,a,[],mu); %yvalues of the linear interpolation
hold off
slope_graph = polyfit(a,yvalues,1);
T = yvalues(1:14);
stand_dev = std(T);
while stand_dev < .03
counter = counter + 1;
T(counter) = yvalues(counter);
stand_dev = std(T);
end
max_ind = find(a,1,'last');
ts_ind = find(yvalues == T(counter),1,'last');
ts = a(ts_ind);
Temperature2 = yvalues(max_ind:-1:ts_ind);
T_2 = Temperature2(1:14);
stand_dev = 0;
counter = 14;
while stand_dev < .03
counter = counter + 1;
T_2(counter) = Temperature2(counter);
stand_dev = std(T_2);
end
yH_ind = find( Temperature2 == T_2(counter),1,'last');
if slope_graph(1) > 0
yL = mean(T)
yH = Temperature2(yH_ind)
else
yL = Temperature2(yH_ind)
yH = mean(T)
end
y_tau = .632 * (yH - yL)
ts
x_tau_t = vpasolve(equation_clean == y_tau,t,[0 Inf])
tau = x_tau_t(end) - ts;
Hello everyone, I need your help.
I am super beginner at Matlab, but have a challenging task in front of me. I want to find out tau value, I calculatd ts and y_tau. Now I just need to plug in value for y_tau and determine x_tau from it. However matlab tells me that the number does not exist, so there is no solution. but when I draw the graph it is obvious that there is a positive interger solution which is close to 1.7 seconds. Any help would be much appreciated. I have used polynomial interpolation or polyval to determine the polynomial equation.

Answers (1)

Walter Roberson
Walter Roberson on 10 Apr 2019
Q: "We need to know what inputs to test with ?"
A: "The inputs are given by the user"
Given that, then we can conclude that you are wrong about there being an error with the program. See attached implementation code.
  3 Comments
Walter Roberson
Walter Roberson on 10 Apr 2019
We do not have your x or your y, and we do not have your function selection_data

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