Extracting Unknown Amount of Columns from Excel Data
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So I am trying to sort datasheets I'm given in excel into rows of 7 columns. And the datasheet I am given could have any amount of columns for any row. So I was hoping for some help.
This is what I have so far, but it can only handle up to column Y in excel. I want to be able to write something that can handle any amount of columns, just given the input file.
L = length(xlsread('Input')); %number of rows
N = 7; %desired number of columns
X = NaN(1,7); %first reorganized row is empty
for i=1:L %reads all input rows
xlRange = sprintf('A%d:Y%d',i,i); %range of columns from A to Y
A = xlsread('Input',xlRange); %brings in input data one row at a time
Z = reshape([A(:);nan(mod(-numel(A),N),1)],N,{}); %shapes the data into rows of 7
Z = Z.'; %switches rows for columns
X = cat(1,X,Z); %desired output in a matrix
end
xlswrite('Output',X) %prints to excel sheec
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Answers (1)
Jeremy Hughes
on 19 Apr 2019
I recommend using READMATRIX if you have access to R2019a, or READTABLE for earlier releases.
A = readmatrix(filename)
Once you have the matrix in MATLAB, you can loop over the rows of the data for processing.
3 Comments
Jeremy Hughes
on 22 Apr 2019
You shouldn't need the READ function (which ever one you're using) to do the looping.
Bring in all the data, then loop over the data. Even in your example:
L = length(xlsread('Input')); %number of rows
Could instead be:
data = xlsread('Input');
L = length(data); %number of rows
Since you're reading in everything already, then throwing it out, then reading it again row by row, you're really doing a lot of wasted work.
A = data(:,i)
I'm not sure what reading row-by-row is doing for your case since I don't have your file.
If you upload an example file, it might be more clear what you're trying to accomplish.
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