## i have a question that works backwards

### Omar Almahallawy (view profile)

on 28 Apr 2019
Latest activity Commented on by dpb

### dpb (view profile)

on 29 Apr 2019
I have a set of values for F and a set of values for D.
When F and D are divided together they give a ratio that I have the answers to in variable X
so
X=F./(D.^5)
ex.
F =[
0.0026 0.0026 0.0026 0.0026 0.0027 0.0027 0.0027 0.0028 0.0028 0.0028]
D =[
0.9652 1.0160 1.0668 1.1176 1.1684 1.2192 1.3208 1.4224 1.5240 1.6256]
X=[0.0024 0.0019 0.0015 0.0012 0.0010 0.0007 0.0005 0.0003 0.0002]
I want code that tells me for which F and which D give me the known answer of X

dpb

### dpb (view profile)

on 28 Apr 2019
Well, individually, however, the variables are monotonic so one could in theory interpolate which is what the crystal ball is saying the OP would want to do...but would be good to know just what is the desired result for sure...
yyaxis left
hLL=plot([F;X].');
ylabel('F, X')
yyaxis right
hLR=plot(D);
ylabel('D')
xlabel('Ordinal number');
legend([hLL;hLR],'F','X','D') The attached data are lacking in significant digits for both D and F but even so, X is relatively smooth.
Omar Almahallawy

### Omar Almahallawy (view profile)

on 29 Apr 2019
the desired output would be
F= 0.0026 0.0026 0.0026 0.0027 0.0027 0.0027 0.0028 0.0028 0.0028
D= 1.0160 1.0668 1.1176 1.1684 1.2192 1.3208 1.4224 1.5240 1.6256
% notice that when the corrosponding values of F and D are divided give us X
(F./(D.^5))
(0.0026./(1.0160.^5))= 0.0024
%FIRST VALUE OF F AND D GAVE US THE FIRST VALUE OF X
and so on for the rest
how can i code this to give me the desired output of which F and D has been used to calculate X RESPECTIVLEY
dpb

### dpb (view profile)

on 29 Apr 2019
That's a trivial Q? as posed; you calculated X_i from F,D_i so the answer is simply "i" for the set of calculated values.
IF you somehow generate the identically-computed X from some other location, then that Xprime value would match one of the originals; to find which one would be simply
indx=find(X==Xprime);
BUT as was noted in the previous comment, that exact lookup will fail almost certainly owing to floating point rounding and precision issues; perhaps ismember could help resolve that particular problem but somehow I don't think you've yet described what you're after sufficiently for us to understand what the objective is here.

on 29 Apr 2019