MATLAB Answers

How to obtain the minimum values of an array?

1 view (last 30 days)
I'm trying to get the minimum values of three vectors. Assuming that the length of the vectors is 1x4, I need to get 4 minimums. Also one of the vectors has as values a constant. I'm attaching the code. The important part is on lines 12 to 15.
function [x_t,Re,eta_c,C_f] = CXAPWING(b,b_slats,x_thickness,x_camber,M)
%%% Коэффициент профильного сопротивления крыла
h_polish = 1e-6; %micro
V = M*299.45;
Re = V*b/3.5232e-5;
F1 = 1.3+0.6*M*(1-0.25*M^2);
hbRe = h_polish*V/3.5232e-5;
F2 = log10(abs(hbRe-1));
F3 = (2.2-0.08*M^2)/(1+0.312*M);
n = 5+F1*(1-(F2/F3)^2)^0.5;
x_t_1 = 10^n/Re;
x_t_2 = sqrt(x_thickness*x_camber);
x_t_3 = b_slats/b;
x_t = min([x_t_1 x_t_2 x_t_3]);
if Re < 4.85e5
C_f = 1.328/sqrt(Re);
elseif Re > 3e7
C_f = 0.455/(log10(Re))^2.58;
else
C_f = (0.455./log10(Re).^2.58).*((1-x_t+(40*x_t^0.625)/Re.^0.375).^0.8)';
end
% nc_xt = [1.4072 1.3722 1.3536 1.3103 1.2557; 0 0.1 0.2 0.3 0.4]; % 0.11
nc_xt = [1.3323 1.3063 1.2917 1.2552 1.2115; 0 0.1 0.2 0.3 0.4]; %0.09
if x_t > 0 && x_t < 0.1
eta_c = INTERPOLATION(nc_xt(2,1),nc_xt(1,1),nc_xt(2,2),nc_xt(1,2),x_t);
elseif x_t > 0.1 && x_t < 0.2
eta_c = INTERPOLATION(nc_xt(2,2),nc_xt(1,2),nc_xt(2,3),nc_xt(1,3),x_t);
elseif x_t > 0.2 && x_t < 0.3
eta_c = INTERPOLATION(nc_xt(2,3),nc_xt(1,3),nc_xt(2,4),nc_xt(1,4),x_t);
else x_t > 0.3 && x_t < 0.4
eta_c = INTERPOLATION(nc_xt(2,4),nc_xt(1,4),nc_xt(2,5),nc_xt(1,5),x_t);
end
end

  0 Comments

Sign in to comment.

Accepted Answer

madhan ravi
madhan ravi on 8 Jun 2019
Have a look at mink() else use sort() and pick the first four values if you’re using older version.

More Answers (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!