## fourier transform of this:

on 28 Jun 2019

on 28 Jun 2019

### KALYAN ACHARJYA (view profile)

hi this is my shape that i want it's fourier transform this is my code:
clc
clear all
t=-3:0.0001:3;
%x=-heaviside(t+2)
%y=t
%z=rectangularPulse(t-1)
%unitstep = t>-1;
%ramp = t.*unitstep;
f= -heaviside(t+2)+ heaviside(t+1)+t.*(t>=-1)-t.*(t>=1)+ heaviside(t-1)-heaviside(t-2)
figure(1)
plot(t,f)
axis([-3,3,-2,2])
FT=fourier(f)
this is error:
Undefined function 'fourier' for input arguments of type 'double'.
Error in Untitled12 (line 19)
FT=fourier(f)
how could i fix this?
the result of my code: ### KALYAN ACHARJYA (view profile)

on 28 Jun 2019
Edited by KALYAN ACHARJYA

### KALYAN ACHARJYA (view profile)

on 28 Jun 2019

FT=fft(f);
First FFT then plot, requested you to read this documentation

Show 1 older comment

on 28 Jun 2019
what is different between fourier (f) and fft(f)?

on 28 Jun 2019
ok final code:
clc
clear all
t=-3:0.0001:3;
%x=-heaviside(t+2)
%y=t
%z=rectangularPulse(t-1)
%unitstep = t>-1;
%ramp = t.*unitstep;
f= -heaviside(t+2)+ heaviside(t+1)+t.*(t>=-1)-t.*(t>=1)+ heaviside(t-1)-heaviside(t-2)
figure(1)
plot(t,f)
axis([-3,3,-2,2])
FT=fft(f)
g = (0:length(FT)-1)*50/length(FT);
figure(2)
plot(g,abs(FT))
axis([-10,60,-2,100])
result:  hope this is true!
KALYAN ACHARJYA

on 28 Jun 2019