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Looping through a matrix with unknown dimensions

Asked by Bubbles Lol on 9 Sep 2019
Latest activity Commented on by Rena Berman on 19 Sep 2019 at 15:49
function [r,g,b] = Distant_Pixel(n)
pixels= gallery('integerdata',54,[1,n,3],42);
[R,G,B] = Median_Pixel(n);
r = Pixel_Distance([R,G,B],[pixels(1,1),pixels(1,1,2),pixels(1,1,3)])
g = Pixel_Distance([R,G,B],[pixels(1,2),pixels(1,2,2),pixels(1,2,3)])
b = Pixel_Distance([R,G,B],[pixels(1,3),pixels(1,3,2),pixels(1,3,3)])
end
Median_Pixel and Pixel_Distance are functions.
Since n will change depending on input. How do I fix the pixels matrix so that it works with any input of n
[pixels(1,1),pixels(1,1,2),pixels(1,1,3)] -- ?

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1 Answer

Answer by Walter Roberson
on 9 Sep 2019

function [r,g,b] = Distant_Pixel(n)
pixels= gallery('integerdata',54,[1,n,3],42);
[R,G,B] = Median_Pixel(n);
r = []; g = []; b = [];
if n >= 1
r = Pixel_Distance([R,G,B],[pixels(1,1),pixels(1,1,2),pixels(1,1,3)]);
end
if n >= 2
g = Pixel_Distance([R,G,B],[pixels(1,2),pixels(1,2,2),pixels(1,2,3)]);
end
if n >= 3
b = Pixel_Distance([R,G,B],[pixels(1,3),pixels(1,3,2),pixels(1,3,3)])
end
end

  2 Comments

The input of the function is a 1*n*3 array. Containing rgb values. I want to find the most distant rgb pixel values from those that are provided in the array. So how would I do this? and n can be any number. Thanks
We do not know what your function Pixel_Distance does.
It is not clear what the most "distance" rgb values means in this situation, since you appear to be talking about 3 different values
Given a set of pixel values, you can take the mean or median . Now for any one median component (say the G), check to see whether the component is above or below 1/2 of the maximum possible value (e.g., 128 if the values are uint8). If the component is below 1/2 of the maximum possible, then the most distant value is the maximum possible value (e.g., 255); if the component is above 1/2 of the maximum possible, then the most distant value is the minimum possible value (e.g., 0)

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